- Display hostname next to IP (where available) in the jQuery IP suggestion...

Falko Timme

2013-10-22 391e05cbee6ff84bce60b665be60b4e5f049ee7f

 interface/lib/classes/functions.inc.php

@@ -238,11 +238,23 @@
         $regex = "/^(\:\:([a-f0-9]{1,4}\:){0,6}?[a-f0-9]{0,4}|[a-f0-9]{1,4}(\:[a-f0-9]{1,4}){0,6}?\:\:|[a-f0-9]{1,4}(\:[a-f0-9]{1,4}){1,6}?\:\:([a-f0-9]{1,4}\:){1,6}?[a-f0-9]{1,4})(\/\d{1,3})?$/i";
      }
   
      $server_by_id = array();
      $server_by_ip = array();
      $servers = $app->db->queryAllRecords("SELECT * FROM server");
      if(is_array($servers) && !empty($servers)){
         foreach($servers as $server){
            $server_by_id[$server['server_id']] = $server['server_name'];
         }
      }
	
      $ips = array();
      $results = $app->db->queryAllRecords("SELECT ip_address AS ip FROM server_ip WHERE ip_type = '".$type."'");
      $results = $app->db->queryAllRecords("SELECT ip_address AS ip, server_id FROM server_ip WHERE ip_type = '".$type."'");
      if(!empty($results) && is_array($results)){
         foreach($results as $result){
            if(preg_match($regex, $result['ip'])) $ips[] = $result['ip'];
            if(preg_match($regex, $result['ip'])){
               $ips[] = $result['ip'];
               $server_by_ip[$result['ip']] = $server_by_id[$result['server_id']];
            }
         }
      }
      $results = $app->db->queryAllRecords("SELECT ip_address AS ip FROM openvz_ip");
@@ -317,7 +329,7 @@
   
         foreach($ips as $ip){
            $result_array['cdata'][] = array(   'title' => $ip,
                                       'description' => $type,
                                       'description' => $type.($server_by_ip[$ip] != ''? ' > '.$server_by_ip[$ip] : ''),
                                       'onclick' => '',
                                       'fill_text' => $ip
                                    );